Comments on 'Cisco Training CCNA IP Addressing - Part 8' |
- yes you're all correct. . 64.255 and 32.255 are both
networks. . don't be confused. . just review the past lessons they haD . . i think it was the part6. .
- I thought .32.255 and .64.255 are network addresses. Could u
pl tell me if I am wrong and why? Bit confused.
- You have to remember the third octet is what we are looking
at. A valid subnet would be 172.16.32.0 and the broadcast of that would be 172.16.47.255 since 48.0 is the next subnet.
- Don't want to confuse anyone, but isn't it true that the
.32.255 and .64.255 adresses are the subnet adresses?
- The 128, 192, etc table is probably the most useful piece of
IP addressing help I've ever seen. Couple that with 256 "magic number" and subnetting becomes so much easier. Thankyou very much!
- Alternative to finding the decimal subnet mask is to start
with 32 - 20 = 12
then 12 - 8 = 4
So you know that you have four host bits in the third octet.
Therefore, the step size (magic number) is 2^4 = 16
From there continue the same way as described in the video.
- Thanks !
I used to calculate the subnet mask for each
address but with your method (the "256 magic number") it's much faster :)
- I like your methods better than Todd Lammle
- superbly explained
- thankx budy
these help me in teaching tcpip to my students
- Please more!!!!
- Thanks! this is great!
- awesome i m your fan ! such a nice explanation. really
thankful
- It was educational !!! more upload sir
- Very Gud
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| Information:4.87 min User rating: 4.5882354/5 Username: panchotraining Views on youtube: 25213
Description: One more example question for the CCNA exam, using both methods seen previously.
Keywords: CCNA, IP, Addressing, Cisco, Network, Academy, 640-802, CCENT, John, Mills, Networking, TCP/IP, Training
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